3x^2+58x-120=0

Solution for 3x^2+58x-120=0 equation:

3x^2+58x-120=0

a = 3; b = 58; c = -120;
Δ = b2-4ac
Δ = 582-4·3·(-120)
Δ = 4804
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4804}=\sqrt{4*1201}=\sqrt{4}*\sqrt{1201}=2\sqrt{1201}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-2\sqrt{1201}}{2*3}=\frac{-58-2\sqrt{1201}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+2\sqrt{1201}}{2*3}=\frac{-58+2\sqrt{1201}}{6}
$